Python-Code

test_data = [
    ([3, 4, 15, 22], 7),
    ([1, 3, 4, 6], 8),
    ([4, 4, 5, 6], 8),
    ([1, 3, 4, 6], 7),
    ([4, 4, 4, 5, 6], 8)
]

def search_target(array, target):
    solution = []
    for index1 in range(len(array)):
        for index2 in range(index1 + 1, len(array)):
            if array[index1] + array[index2] == target:
                solution.append((index1, index2))
    print(f'arr = {array}')
    print(f'target = {target}')
    if solution:
        print(f'Index = {solution}\n')
    else:
        print(f'No Solution\n')

for array, target in test_data:
    search_target(array, target)

Python-Code

def get_index(arr, target):
    index = []
    for i in range(0, len(arr) - 1):
        for j in range(i + 1, len(arr)):
            if arr[i] + arr[j] == target:
                index.append([i, j])
                # folgende Kommentierung für die leichten Beispiele entfernen
                '''break'''
            else:
                continue
            if arr[i] + arr[j] > target:
                break
        # folgende Kommentierung für die leichten Beispiele entfernen
        '''if index:
            break'''
    if not index:
        index = [[0, 0]]
    return index


input_arr = [4, 4, 4, 5, 6]
input_tar = 8
print(get_index(input_arr, input_tar))

Python-Code

# 303 Zielwertsuche in einem sortierten Array

# --------------------------------
arr = [3, 4, 15, 22]
target = 7
#Index = [0, 1] (3+4)

arr1 = [1, 3, 4, 6]
target1 = 8
Index = []

def Aufgabe1(list, target):
    n = 2
    for i in list:
        if i <= target:
            if n > 0:
                target -= i
                Index.append(list.index(i))
                n -= 1
                if target == 0:
                    return Index
    if target > 0:
        Index.clear()
        return Index
            
print( 'Index =', Aufgabe1(arr, target))
print( 'Index =', Aufgabe1(arr1, target1))

# --------------------------------
arr3 = [4, 4, 5, 6]
target3 = 8
Index = []
#Index = [0, 1] (4+4)

def Aufgabe2(liste,target):
    n = 2
    for e in range(len(liste)-1):
        if liste[e] <= target:
            if n > 0:
                target -= liste[e]
                Index.append(e)
                n -= 1
                if target == 0:
                    return Index
    if target > 0:
        Index.clear()
        return  
    
print( 'Index =', Aufgabe2(arr3, target3))

# -------------------------------------
import itertools

arr4 = [1, 3, 4, 6]
target4 = 7
Index = []
#Indizes = [0, 3] (1+6), [1, 2] (3+4)

def rotate(r):    
    r.append(r.pop(0))
    return(r)

def Aufgabe3(liste,target):
    for i in itertools.permutations(liste,2):
        if sum(i) == target:
            l=[]
            for e in i:
                l.append(liste.index(e))                     
            Index.append(l)
    # doppelte entfernen
    Indizes = []
    for i in Index:
        if i not in Indizes and rotate(i) not in Indizes:
            Indizes.append(rotate(i))   

    return(Indizes)
            
print('Indizes =', Aufgabe3(arr4, target4) )

    

Python-Code

arr = [1, 3, 4, 6]
target = 7
a = 0
while a < len(arr):
    for i in range(a+1 ,len(arr)-a):
        sum =(arr[a] +arr[i])
        if  sum == target:
            print("[ "+ str(a)+ " , "+str(i)+"]")
    a +=1

Python-Code

def search(data, tar):
    k = range(len(data))
    res = [tuple(ij) for ij in {frozenset((i, j)) for i in k for j in k if i != j and data[i] + data[j] == tar}]
    res.sort()
    if res:
        return {ij: f"{data[ij[0]]} + {data[ij[1]]} = {tar}" for ij in res}
    else:
        return "Keine Lösung"

# Test:


testdata = [([3, 4, 15, 22], 7),
            ([1, 3, 4, 6], 8),
            ([4, 4, 5, 6], 8),
            ([1, 3, 4, 6], 7),
            ([4, 4, 4, 5, 6], 8)]

for row in testdata:
    print(search(row[0], row[1]))