C# :: Aufgabe #7 :: Lösung #10
15 Lösungen
#7
Übung mehrdimensionales Datenfeld welches aus zufälligen Inhalten besteht darstellen
Anfänger - C#
von Gustl
- 30.07.2012 um 23:37 Uhr
#10
von Shirkova (190 Punkte)
- 03.07.2016 um 15:59 Uhr
using System;
using System.Collections.Generic;
using System.Linq;
using System.Text;
using System.Threading.Tasks;
namespace ConsoleApplication3
{
class Program
{
static void Main(string[] args)
{
int[,,] arr = new int[6,3,4];
Random r = new Random();
string print_array = "";
string print_position = "";
int minimum = int.MaxValue;
//Initialize the array and prepare String print_array for printing out the array. Also remember the lowest value inserted.
for(int i = 0; i < arr.GetLength(0); i++)
{
for(int j = 0; j < arr.GetLength(1); j++)
{
print_array += "( ";
for(int x = 0; x < arr.GetLength(2); x++)
{
arr[i, j, x] = r.Next(20, 31);
print_array += arr[i, j, x] + " ";
if(minimum > arr[i,j,x])
{
minimum = arr[i, j, x];
}
}
print_array += ") ";
}
print_array += "\n";
}
//Loop through array and find positions of lowest value. Prepare String print_position for printing out the positions of the lowest values.
for (int i = 0; i < arr.GetLength(0); i++)
{
for (int j = 0; j < arr.GetLength(1); j++)
{
for (int x = 0; x < arr.GetLength(2); x++)
{
if(arr[i,j,x] == minimum)
{
print_position += string.Format("Zeile: {0} Gruppe: {1} Element: {2} \n",i,j,x);
}
}
}
}
Console.WriteLine(print_array);
Console.WriteLine();
Console.WriteLine("Minimum: {0}, an Position: ", minimum);
Console.WriteLine(print_position);
Console.Read();
}
}
}
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